Php-mysql Course

To replace variables in string with their values defined in php, you can use the strtr() or preg_replace_callback() function.

Example with strtr()

- Click to select it.
<?php
// array with data for the variables added in string
$data = array(
  '{$site}'=>'https://coursesweb.net/',
  '{$year}'=>date('Y')
);
$str = 'Code-snippets from {$site} , added in: {$year}.';

$str2 = strtr($str, $data);
echo $str2;      // Code-snippets from https://coursesweb.net/ , added in: 2014.

Example with preg_replace_callback()

- Click to select it.
<?php
// array with data for the variables added in string
$data = array(
  'id'=>'test2',
  'domain'=>'CoursesWeb.net'
);
$str = '<div id="{$id}">Parse this string, interpret {$domain} </div>';


$str2 = preg_replace_callback('/{\$([^}]+)}/', function($m) {
  GLOBAL $data;
  return $data[$m[1]];
}, $str);

echo $str2;      // <div id="test2">Parse this string, interpret CoursesWeb.net </div>
- It is important to define data for variables into an Array with the keys that match the form you added the variable in string. Interpreting variables in string can also be useful to create and use template page; see this tutorial: Create and Use in PHP a Simple Template Page.

Daily Test with Code Example

HTML
CSS
JavaScript
PHP-MySQL
What attribute makes an option from <select> selected?
checked="checked" selected="selected" disabled="disabled"
<select name="a_name">
 <option value="val1">Option 1</option>
 <option value="val2" selected="selected">Option 2</option>
</select>
What CSS value allows to create color gradients for background?
contain repeat-x linear-gradient
#id {
  background: linear-gradient(top left, #1f1, #fff, #11f);
}
What statement creates an array in JavaScript?
[] {} new Object()
var arr = [1, "CoursesWeb.net", "MarPlo.net"];
alert(arr[2]);
Indicate the PHP function used to redirect to other page.
function() header() switch()
header("Location: http://coursesweb.net/");
exit;
Interpret / Parse / Replace variable in string with value

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